81x^2+7=107

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Solution for 81x^2+7=107 equation:



81x^2+7=107
We move all terms to the left:
81x^2+7-(107)=0
We add all the numbers together, and all the variables
81x^2-100=0
a = 81; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·81·(-100)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*81}=\frac{-180}{162} =-1+1/9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*81}=\frac{180}{162} =1+1/9 $

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